w^2-3w=1890

Solution for w^2-3w=1890 equation:

w^2-3w=1890

We move all terms to the left:

w^2-3w-(1890)=0

a = 1; b = -3; c = -1890;
Δ = b2-4ac
Δ = -32-4·1·(-1890)
Δ = 7569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7569}=87$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-87}{2*1}=\frac{-84}{2}
=-42
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+87}{2*1}=\frac{90}{2}
=45
$